Question

a) One Covid 19 positive patient can
infect an average of 1.7 persons if left
unquarantined.
b) Success rate of keeping the patients
under quarantined immediately without
further infection be x%
c) On 1st June, India had approximately 1
Lakh active Covid 19 cases.
Find the integer nearest to x so that the
active cases do not increase from the 1st
June level.​

Answer 1

Given : One Covid 19 positive patient can infect an average of 1.7 persons if left unquarantined.

To find : the integer nearest to x so that the active cases do not increase from the 1st June level.

Solution:

there should be recovery rate mentioned to find exact solution.

but seeing the options looks like user want solution as below

active cases 1st june = 100000

quarantined successfully = x%

= (x/100)100000 = 1000x

unquarantined = 100000 - 1000x

= (1000)(100 - x)

infected per unquarantined = 1.7 person

Total infected = 1.7 × 1000(100-x)

infected should be less than 100000

=> 1.7 ×1000(100 - x) < 100000

=> 1.7 (100 - x) < 100

=> 170 - 1.7x < 100

=> 1.7x > 70

=> x > 70/1.7

=> x> 41.17

=> x = 42

rate of keeping the patients under quarantined immediately without

further infection be 42 %

x = 42

learn more:

इस हॉस्पिटल मे 16 कोरोना के मरीज हे, 13 नंबर का ...

brainly.in/question/17170505

One Covid 19 positive patient can  infect an average of 1.7 persons

https://brainly.in/question/18317010