Physics, asked by shehzashehzadi50, 1 year ago

a one kilo stone falling freely from a height of 10 m , strikes the ground with a velocity of​

Answers

Answered by JoshuaFerns
4

Answer:

let us first find time,

h = 10m

g = 10m/s (we use 10 for easy calculation)

so, h = 1/2gt^2

10 = 1/2 *10 t^2

2 = t^2

t = √2 sec

we know, v = gt

v = 10(√2)

therefore, v = 10√2 m/s

Answered by gauravkumar1301gk
1

Answer:

Explanation:

h=10m

g=10m/s^2

u=10m/s

Using kinematics equation for a falling object:

v^2-u^2=2gh

v^2-0=2*10*10

v^2=200

v=√200

v=10√2 m/s

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