Question

A one microfarad capacitor of a TV is subjected to 4000V potential difference. The energy stored in capacitor is:

Answer 1

Answer:

Given, capacitor C=10^−6 F and potential difference V=4000V

The energy stored in capacitor = 1/2 CV^2

= 1/2 × 10^-6 × (4000)^2 = 8J

Explanation:

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Answer 2

Answer:

Explanation:

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