Question

A open ended mercury manometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Initially manometer shows no difference in mercury level in both columns as shown in diagram. ure After sparking 'A' dissociates according to following reaction Ag)- B(g)+3C(g). If pressure of Gas "A" decreases to 0.9 atm. Then (Assume temperature to be constant and is 300 K) (a) total pressure increased to 1.3 atm (b) total pressure increased by 0.3 atm (c) total pressure increased by 22.3 cm of Hg (d) difference in mercury level is 228 mm.​

Answer 1

Answer:

Both options B and D are correct.

Explanation:

Pi=76cm of Hg=1 atm PA =1 atm

2A(g)→3B(g)+2C(g)

$P_{A final} =0.8$

1-2x=0.8

x=0.1

$P_{B} =3*0.3=0.3$

$P_{c} =2*0.1=0.2$

$P_{total} =0.8+0.2+0.3=1.3atm$

$P_{increase} =0.3atm=0.3*760$

=228mm of Hg