Chemistry, asked by pallatikavyasri, 25 days ago

A open vessel at 25° at heated until 3/5 of the air is it in remained. The temperature to which the vessel must be heated to achieve this is

Answers

Answered by ITZURADITYAKING
1

Answer:

Given the vessel is open, its volume remains constant. Therefore, the pressure will also be constant. We have the following two general gas equation:

PV=n1RT1PV=n1RT1 and PV=n2RT2PV=n2RT2

where n1n1, n2n2 are the numbers of moles and T1T1, T2T2 are the temperatures.

Thus,

n1RT1=n2RT2n1RT1=n2RT2

or n1T1=n2T2n1T1=n2T2

Let the initial number of moles be 11.

Number of moles remaining =1−35=25=0.4=1-35=25=0.4

T1=27+273=300KT1=27+273=300K, T2=?T2=?

Putting the values in above equation, we get

1×300=0.4×T21×300=0.4×T2

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