A open vessel at 25° at heated until 3/5 of the air is it in remained. The temperature to which the vessel must be heated to achieve this is
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Given the vessel is open, its volume remains constant. Therefore, the pressure will also be constant. We have the following two general gas equation:
PV=n1RT1PV=n1RT1 and PV=n2RT2PV=n2RT2
where n1n1, n2n2 are the numbers of moles and T1T1, T2T2 are the temperatures.
Thus,
n1RT1=n2RT2n1RT1=n2RT2
or n1T1=n2T2n1T1=n2T2
Let the initial number of moles be 11.
Number of moles remaining =1−35=25=0.4=1-35=25=0.4
T1=27+273=300KT1=27+273=300K, T2=?T2=?
Putting the values in above equation, we get
1×300=0.4×T21×300=0.4×T2
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