Question

A open vessel at 27°c is heated until 1/4thor the air in it has been expelled.Assuming that the vessel remains same,the temperature at which the vessel was heated is

Answer 1

We have, if initial mole of the gas at 27∘C be n=n1

On heating 3 / 8 mole of air escapes at temperature T.

Therefore, mole of air left at T=n–3n8=5n8=n2.

Under initial condition of P and V, n1T1=n2T2

Or, n×300=5n8×T

Or, T=480K=206.85∘C.

IF U LIKED THIS ANS PLEASE MARK IT AS BRAINLIEST