Question

a open vessel of volume of vl when heated from 27^0c

Answer 1

2 answers · Chemistry

Answers

Charles' Law (air is an ideal gas) : V1/T1 = V2/T2

Let x be the volume of the vessel. The volume of the air at the start (V1) is x. After heating, 2/5 of the air fills a volume of x. Assuming uniform expansion:

(2/5)(V2)=x => V2=(5/2)(x)=5x/2

27 Celsius = 300 Kelvin

Subbing in: x/300 = (5x/2)/T2

x cancels on both sides and solving for T2 we get: T2 = 1500/2 = 750 K = 477 C