Question

a owner increases the rent of his house by 5% at the end of each year if currently it's rent is rupees 2500 per month how much will be the rent after 2 years​

Answer 1

Answer:

2827.25 rupees per month(this is technically the 3rd year)

Step-by-step explanation:

5% out of 2500=65 rupees;  2500+65=2565 rupees per month the next year resulting in rent of 30.780 rupees per year

5% out of 2565= 128.25; 2565+128.25=2693.25 rupees per month the next year resulting in rent of 32.319 rupees per year

if the next year the owner increases again the rent by 5%:

5% out of 2693.25=apx 134; 2693.25+134=2827.25 rupees per month resulting in 33927 rupees per year.

Answer 2

Given:-

• A owner increases the rent of his house by 5%. at the end of each year. If currently its rent is ₹ 2500 per month, how much will be the rent of after 2 years?

To Find:-

• How Much will be the rent after 2 years.

Used Formula:-

${\large{\green{\tt{☆}}}} \: \: \: \: {\underline{{\boxed{\pink{\bf{A \: = \: P \: \: \bigg[1 \: + \: \frac{R}{100}{\bigg]}^{n}}}}}}}$

Solution:-

R = 5 % ( Yearly one increasing )

T = 2 years ( n = 2)

$⇒ \: \: {\sf{A \: = \: P \: \: \bigg[1 \: + \: \frac{R}{100}{\bigg]}^{n}}}$

$⇒ \sf\ \: 2500 \: \bigg[1 \: + \: \dfrac{5}{100}\bigg]$

$⇒ \sf\ \: 2500 \: \: \bigg( \dfrac{105}{1 {00}} \bigg)^{2}$

$\\ ⇒ \sf\ \: {\cancel{2}}5{\cancel{0}}{\cancel{0}} \: \times \: \dfrac{105}{1{\cancel{0}{\cancel{0}}}} \: \times \: \dfrac{105}{{\cancel{100}}} \: \: \: (This \: Number \: has \: doubled \: due \: to \: square )$

$⇒ \sf\ \: \dfrac{105 \: \times \: 105}{4}$

$⇒ \sf\ \: \dfrac{11025}{4}$

$⇒ \sf\ \: 2756 \: \frac{1}{4}$

$⇒ \sf\ \: {\boxed{\red{\sf{2750.25}}}}$

$\rule{100mm}{1pt}$

2750.25 is the rent after 2 years.