Question

A.P. 5,8,11,14,... का 10वां पद है

Answer 1

$Given \: A.P : 5,8,11,14,\ldots$

$First \:term (a = a_{1}) = 5$

$Common \: difference (d) = a_{2} - a_{1}$

$= 8 - 5$

$= 3$

/* We know that , */

$\boxed{ \pink { n^{th} \: term (a_{n}) = a + (n-1)d }}$

$Here, a = 5 , d = 3 \:and \: n = 10$

$10^{th}\: term = a_{10}$

$= a + (10-1)d$

$= a + 9d$

$= 5 + 9 \times 3$

$= 5 + 27$

$= 32$

Therefore.,

$\red{ 10^{th}\: term} \green { = 32 }$

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Answer 2

Answer:

hey here is your answer

A.P.= 5,8,11,14,....

where,

a = 5

n = 10

d = 8 - 5 = 3

an = a + ( n - 1 ) d

= 5 + (10 - 1) * 3

= 5 + 9 * 3

= 5 + 27

= 32

so, an is 32