Question

A.P.
7. Find the 318 term of an A.P. whose 11th
term is 38 and the 16" term is 73. (AS)
S​

Answer 1

Answer:

A318 =2187

Step-by-step explanation:

for nth term of AP

An=A1+(n-1)d

n is the no. of term and A1 is the first term d is common difference

73-38=35

so difference between 11th and 16th is 35 and we know that AP has a fix common difference between consecutive term

after 11 to 16th term there is 5 term

which is equally divided by 35

so

35/5=7

7 is the d

now for 318 term

A318= -32+(318-1)7 ( A1 is -32(A11 to A1 is 10 term 7×10=70, 38-70=-32)

A318=2187