A.p a3=15 s10=125 find d and a10
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Answered by
17
a3=15. d=?
S10=125. A10=?
a3=a+2d
15=a+2d
a=15-2d
S10=125
S10=10/2[2a+9d]
S10=5(2a+9d)
125=5[2(15-2d)+9d]
25=30-4d+9d
-5=5d
d=-1
putting the value of d in 15=a+2d,
15=a- 1.2
a=17
A10=a+9d
A10=17-9=8
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Answered by
1
Answer:
an=a+(n-1)d
a3=a+(3-1)d
15=a+2d
a+2d=15 _________ {1}
Sn=n/2(2a+{n-1}d)
S10=10/2(2a+{10-1}d)
125=5(2a+9d)
125/5=2a+9d
25=2a+9d ___________{2}
solving eq{1} & eq{2}
putting a value in eq {2}
2(15-2d)+9d=25
30-4d+9d=25
5d=25-30
=-5
=d=-1
=>an=a+(n-1)d
a10=a+(10-1)d
a10=a+9d
a10=17+9(-1)
a10=17-9
a10=8
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