Question

a)P and Q are centres of circles of radius 9 cm and 2 cm

Respectively. R is the centre of a circle of radius x cm which

Touches the two circles . PRQ = 90˚, write the equation in

x and solve it .​

Answer 1

Step-by-step explanation:

by pythaorous theorem ,

PQ²=QR²+PR²

17²=(X+2)²+(X+9)²

289=X²+4+2X+X²+81+18X

0=2X²+20X+85-289

0=2X²+20X+204

0=X²+10X+104

SOLVE THE EQUATION AND GET THE VALUE OF X...PLZ MARK ME AS BRAINLEIST