a)P and Q are centres of circles of radius 9 cm and 2 cm
Respectively. R is the centre of a circle of radius x cm which
Touches the two circles . PRQ = 90˚, write the equation in
x and solve it .
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Step-by-step explanation:
by pythaorous theorem ,
PQ²=QR²+PR²
17²=(X+2)²+(X+9)²
289=X²+4+2X+X²+81+18X
0=2X²+20X+85-289
0=2X²+20X+204
0=X²+10X+104
SOLVE THE EQUATION AND GET THE VALUE OF X...PLZ MARK ME AS BRAINLEIST
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