A p.d of 200v is applied at the ends of filament of a bulb of resistance 200 ohm . what is the power of the bulb
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Answered by
1
Answer:
200 watt
,
Explanation:
p. d(v):200v
resistance(R):200 ohm
power:v^2/R
:200^2/200
:200 watt answerrrrrrrrr
I hope this will help uuh
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