Physics, asked by swastikbiyani5, 1 year ago

A p.d. of 6 V is applied to two resistors of 3Ω and 6Ω connected in parallel. Calculate:
(a) the combined resistance
(b) the current flowing in the main circuit
(c) the current following in the 3Ω resistor

Answers

Answered by ankit7958

The current flowing in the main circuit

swastikbiyani5: (a) When two resistors are connected in series, their resultant resistance is given by
R = R1+ R2
Here, R1=6 Ω,
         R2=2 Ω
Therefore
The resulatant resistance, R = 6 + 2 = 8 Ω

(b) The current flowing through circuit is:
   V = IR
   I = V/R = 4/8
   I = 0.5 A

(c) The p.d. across the 6 Ω resistor is:
   V = 0.5 A x 6 Ω = 3 V

ankit7958: hi

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A p.d. of 6 V is applied to two resistors of 3Ω and 6Ω connected in parallel. Calculate:(a) the combined resistance(b) the current flowing in the main circuit(c) the current following in the 3Ω resistor

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A p.d. of 6 V is applied to two resistors of 3Ω and 6Ω connected in parallel. Calculate:
(a) the combined resistance
(b) the current flowing in the main circuit
(c) the current following in the 3Ω resistor