A.P. if T¹=22,Tn=-11 and Sn=66 then find n term
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Tn=a+(n-1)d and then use sn=n/2 2a+(n-1)d
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Answered by
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Answer:
12 Terms
Step-by-step explanation:
T₁ = 22 = a
Tn = -11
Tn = a + (n-1)d
-11 = 22 + (n-1)d
(n-1)d = -33
Sn = (n/2)( a + a + (n-1)d)
Sn = (n/2)(2a + (n-1)d)
66 = (n/2) (2×22 + (-33) )
66 = (n/2)(44 -33)
66 = (n/2) (11)
6 = n/2
n = 12
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