Question

a p-n junction with depletion layer of 1 micro metre has a potential barrier of 0.2V. find the intensity of electric field at the junction​

Answer 1

Answer:

E= V ÷ m

  = 0.2 ÷ 10⁻⁶

  = 0.2 × 10⁶ N/C

Answer 2

The intensity of electric field at the junction​ is $2\times 10^5\ V/m$

Explanation:

Given that,

The potential barrier of a pn junction, V = 0.2 volts

Width of the depletion layer, $d=1\ \mu m=10^{-6}\ m$

We need to find the intensity of electric field at the junction​. We know that the relation between the electric field and the electric potential is given by :

$E=\dfrac{V}{d}\\\\E=\dfrac{0.2\ V}{10^{-6}\ m}\\\\E=2\times 10^5\ V/m$

So, the intensity of electric field at the junction​ is $2\times 10^5\ V/m$. Hence, this is the required solution.

Learn more,

Relation between electric field and electric potential

https://brainly.in/question/8464331