Question

(a) p(x)=√7 is a polynomial of degree ______
(b) if √10=3.1622 then the value of 1/√10 is ______________

Answer 1

1. [tex]p(x)= \sqrt{7} \\ = \sqrt{7} x^{0} [/tex]
hence, power of p(x) is 0
2. $\frac{1}{ \sqrt{10} } \\ = \frac{1}{ \sqrt{10} }( \frac{ \sqrt{10} }{ \sqrt{10} }) \\ = \frac{ \sqrt{10} }{10}$
=3.1622÷10
=0.3622

Answer 2

P(x) = √7  is same as √7 x⁰ 

So √7 is a polynomial of degree zero.

$\sqrt{10} = 3.1622 \\ \\ \frac{1}{\sqrt{10}} = \frac{10}{10 \sqrt{10}} = \frac{\sqrt{10}\sqrt{10}}{10\sqrt{10}} \\ \\ \frac{\sqrt{10}}{10} = \frac{3.1622} {10} = 0.316622$