A pa purse contains rupees 5000 in notes of denominator of rupees hundred and rupees 500 if the total number of nodes is 30 find the number of notes of each denomination
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Answer:
5 notes (Rs.100) and 25 notes (Rs.500)
Step-by-step explanation:
Let, no. of 500 rupee notes be x.
So, no. of 100 rupee notes = 30 - x
Value of 500 rupee notes = Rs. 500x
Value of 100 rupee notes = Rs. 100 ( 30 - x )
= Rs. 3000 - 100x
ATQ, 500x + 300 - 100x = 5000
400x = 5000 - 3000
x = 2000/400
= 5
So, No. of 500 rupee notes = 5 ( ANS )
No. of 100 rupee notes = 30 - 5
= 25 ( ANS )
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