Physics, asked by sghawri3378, 5 hours ago

a package of aluminum foil contain 75ft2 of foil which weighs 12.00 OZ

Answers

Answered by savitagharge2009
0

Answer:

v = lwh, h = v/lw

A package of aluminum foil contains 50 ft2 of foil, which weighs approximately 9.0 oz . Aluminum has a density of 2.70 g/cm3

area = lw = 50 ft^2

So, now we have h = v/50 ft^2

9.0 oz x 28.3495g/1 oz = 255.1455 g

1 cm^3/2.70 g x 255.1455 g = 94.5 cm^3

94.5 cm^3 x (1 in/2.54cm)^3 = 5.8 in^3

5.8 in^3 x (1ft/12 in)^3 = .003337 ft^3

h = vol/50 ft^2 = .003337ft^3/50 ft^2 =

6.67 x 10^-5 ft thick.

(6.67 x 10^-5 ft) x (12 in/1 ft) x (2.54cm/1in) x (10 mm/cm) =.0203

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