Question

a packet if size 5000 bytes is sent over a 100 kilobytes per second point to point link whose propogation delay in 5 msec . the packed will reach the destination after___msec​

Answer 1

A 1000 byte packet is sent over a 50

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-point

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destination

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationafter

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo Bytes

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=Time 8/50 Sec

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=Time 8/50 Sec= 8 * 20 msex

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=Time 8/50 Sec= 8 * 20 msex= 160 msec

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=Time 8/50 Sec= 8 * 20 msex= 160 msecDelay of 10 msec

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=Time 8/50 Sec= 8 * 20 msex= 160 msecDelay of 10 msecThe packet will reach the destination

A 1000 byte packet is sent over a 50kilo-bits-per-second (Kbps) point-to-pointlink whose propagation delay is 10 msec.The packet will reach the destinationaftermsec.1 Byte = 8 Bits=> 1000 Bytes = 1000*8 = 8000 Bits = 8Kilo BytesSpeed 50 kilo bytes per sec=Time 8/50 Sec= 8 * 20 msex= 160 msecDelay of 10 msecThe packet will reach the destinationafter 160 + 10 = 170 msec

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Answer 2

Answer:

Micro seconds to transmit the packet on the link, after which it takes an additional 10 micro seconds for the last bit to propagate across the link.

Explanation:

(Assume 1K = 1000)For each link, it takes

1 Gigabits/5Kb = 5

micro seconds to transmit the packet on the link, after which it takes an additional 10 micro seconds for the last bit to propagate across the link.

1 Byte = 8 Bits

=> 5000 Bytes = 5000*8 = 40000 Bits = 8 Kilo Bytes

Speed  = 100 kilo bytes per sec

Time = 8/100Sec

= (8 * 100)/100 msec

= 8  * 50  msec

= 400 msec

Delay of 5 msec

The packet will reach the destination after,

400 + 5 = 405 msec