Question

A packet is dropped from a balloon rising up with uniform velocity 9.8m/s if the balloon is at
a height of 39.2 m from the ground at the time of dropping the Stone,the stone reaches the ground after
(A)2s

(B) 6s
(C)4S
(D)8s​

Answer 1

Answer:

4 secs

Explanation:

Given A packet is dropped from a balloon rising up with uniform velocity 9.8m/s this mean initial velocity if considered downward = -9.8 m/s

Initial velocity(u) = -9.8 m/s.

Distance covered by it (S) = 39.2 m.

Acceleration(a) = g = 9.8 m/s².

Using the formula,

S = ut + 1/2 × at²

=> 39.2 = -9.8 × t + (1/2) × 9.8 × t²

=> 39.2 = -9.8t + 4.9t²

=> t² - 2t = 8 [Dividing each term by 4.9]

=> t² - 2t - 8 = 0

=> t² - 4t + 2t - 8 = 0

=> t(t - 4) + 2(t + 4) = 0

=> (t - 4)(t + 2) = 0

=> t = 4 and t = -2

t = -2 is not possible as time can never be negative.

Thus, time taken by the particle is 4 seconds.

Answer 2

Answer:

(C) 4s

Explanation:

see In the ATTACHMENTS....

Hope it helps out................