A packet is dropped from a helicopter rising up with velocity 2 ms-¹ . The velocity of the packet after 2 seconds will be
Answers
Answered by
16
Answer:
18m/s
Explanation:
initial velocity =2m/'s , time = 2 's ,
g= -10 m/'s
then using formula v=u-at we get v=18 m/s
Answered by
6
Answer:
The velocity of the packet is 17.6 m/s.
Explanation:
Given that,
Time = 2 sec
Initial velocity = 2 m/s
We need to calculate the velocity
Using equation of motion
Where, v = final velocity
u = initial velocity
g = acceleration due to gravity
t= time
Put the value in the equation
Negative sign shows the downward direction
Hence, The velocity of the packet is 17.6 m/s.
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