Question

A packet is dropped from a helicopter rising up with velocity 2 ms-¹ . The velocity of the packet after 2 seconds will be

Answer 1

Answer:

18m/s

Explanation:

initial velocity =2m/'s , time = 2 's ,

g= -10 m/'s

then using formula v=u-at we get v=18 m/s

Answer 2

Answer:

The velocity of the packet is 17.6 m/s.

Explanation:

Given that,

Time = 2 sec

Initial velocity = 2 m/s

We need to calculate the velocity

Using equation of motion

$v =u+gt$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

t= time

Put the value in the equation

$v = 2+(-9.8)\times2$

$v= -17.6\ m/s$

Negative sign shows the downward direction

Hence, The velocity of the packet is 17.6 m/s.