A packet is dropped from a helicopter, which is ascending at a rate of 16m/s, when it is at a height of 14.4m above the ground. I. How much time it will take the packet to reach the ground? Ii. With what velocity it will hit the ground?
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Answer:
t = 1.6s
Explanation:
Use this
v = u + at
u = 16 , a = -10 , v = 0
substitute to get the value of t
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