Question

A packet is dropped from a helicopter, which is ascending at a rate of 16m/s , when it is at a

height of 14.4m above the ground.

(i) How much time it will take the packet to reach the ground?

(ii) With what velocity it will hit the ground?​

Answer 1

Answer:

Given,

Velocity of the balloon = initial velocity of the food packet u=14

j

^

ms

−1

Gravity acceleration a=−9.81

j

^

m/s

2

Distance from ground h=−98

j

^

m

Final velocity =v & time taken to reach the ground =t

Apply second kinematic equation

v

2

−u

2

=2ah

v=

2ah+u

2

v=

2(−9.81)(−98)+14

2

v=−46

j

^

m/s

Apply first kinematic equation

v=u+at

t=

a

v−u

=

−9.81

−46−14

=6.11 sec

At velocity 46m/s and in time 6.11 sec it will reach to the ground.