Question

a packet is full of 10 similar laddoos. a child is told to pick a maximum of 1 ladoo. how many choices he has? select one: a. 20 b. 100 c. 10 d. 2

Answer 1

We know the the number of $m$ combinations different objects from $n(n\geq m)$ is given by

$\frac{n!}{m!(n-m)!} ,m=0,1,2,...,n$.

Here we have 10 objects and we have to choose maximum 1 from the 10 objects.

Here $n=10,m=1$.

apply the above formula, we get

$\frac{10!}{1!(10-1)!} =\frac{10!}{9!} =10$.

The child can pick the laddus in 10 ways.

Correct answer is (C).