A packet is released from a balloon ascending vertically with a speed of 20m/s. the packed rechesthe ground in16s. find the height of the balloon at the time the packet was relesed
Answers
Answered by
9
u =20m/s
t=16 sec
a=-9.8m/s
s =ut+1/2at^2
=20×16+1/2×-9.8×16×16
-1290.4 is the correct answer
t=16 sec
a=-9.8m/s
s =ut+1/2at^2
=20×16+1/2×-9.8×16×16
-1290.4 is the correct answer
alia61:
this ans is not right
why
the displacement will come in negative
I.e. _934.4m
plz chake ur ans
now is it okk
no yrr
ur ans is totally wrong
the ans will 934.4m
Answered by
4
ANSWER : 960m
Explanation:
WE KNOW, U = 20 m/s , a= -g = -10 m/s
T = 16 s
therefore, S = ut +1/2 at*t
S = 20 * 16 + 1/2 * -10 * 16 *16
S = 20*16 -5 * 256
S = 320 - 1280
S =- 960
therefore S = 960 m
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