Question

A packet of plain biscuits costs Rs. 6 and that of chocolate biscuits costs Rs. 9. A
house wife has Rs. 72 and wants to buy at least three packets of plane biscuits and
it least four packets of chocolate biscuits. How many of each type should she buy
so that she can have maximum number of packets? Form an LPP and solve it
graphically.​

Answer 1

Step-by-step explanation:

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Answer 2

she can have maximum 12  packets

Step-by-step explanation:

let number of plain biscuit packet = x

let number of chocolate biscuit packet = y

she wants to buy 3 packet of plain and  4 packet of chocolate biscuit

total cost of 3 packet of plain and  4 packet of chocolate biscuit = 3 (6) +4(9) = Rs. 54

ans we have to maximize for the remaining amount

maximize Z = x+y

therefore ,

$6x +9y \leq 18\\\\2x+3y \leq 6$

$x\geq 0\\\\ y\geq 0$

plotting these points we find the feasible region with the vertices

(0,0) , (0,2) and (3,0)

from the graph it is clear that

Z is maximum at (3,0)

so , (3,0) is the optimum point

then

total number of packet = 3 + 4+ 3 = 12 packets

hence , she can have maximum 12  packets

#Learn more:

If a box of chocolates costs Rs 95 and a packet of biscuits costs Rs 25, what is the total cost  for 120 boxes of chocolates and 300 packets of biscuits?

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