Question

A packet of plain biscuits costs Rs. 6 and that of chocolate biscuits costs Rs. 9. A
house wife has Rs. 72 and wants to buy at least three packets of plane biscuits and
it least four packets of chocolate biscuits. How many of each type should she buy
so that she can have maximum number of packets? Form an LPP and solve it!
graphically
U
COTTON​

Answer 1

7x9=72

therefore she could buy 9 packets of 7 rs and 7 packets of 9 rs

Answer 2

1.She can have a total of 10 biscuits which contains 6 plain biscuits and 4 chocolate biscuits.

2.consider x for the number of packets of plane biscuits

consider y for the number of packets of chocolate biscuits.

now minimum she wants to buy of rs 54 that contains 3 plain and 4 chocolate biscuits.

so we have to maximize the remaining amount

3.so Maximize Z=x+y

forming equations

6x+9y≤18,

2x+3y≤6

x≥0

y≥0

4. Now we have to plot all the points on a graph paper

before plotting we get the points as (0,0),(0,2),(3,0)

5. we can observe Z is maximum at (3,0)

so total number of packets =3+3+4=10