Question

A packet of sweets is distributed among A, B, C, D in the proportion of 6:8:5:4. If B gets 10
sweets more than D then what is A's share?
- B] 17
C] 15
D] 18
A] 16
​

Answer 1

Answer:

18 I think. but I am not sure about the answer

Answer 2

Given,

A:B:C:D = 6:8:5:4 and B = D + 10

To Find,

The Value of A.

Solution,

B:D = 8:4

⇒ $\frac{B}{D} = \frac{8}{4}$

⇒ $\frac{D+10}{D} = 2$

⇒ $D = 10$

⇒ $B = D+10 = 20$

Next A:B = 6:8

⇒ $\frac{A}{B} = \frac{6}{8}$

⇒ $A = B$×$\frac{3}{4}$

⇒ $A= 20$×$\frac{3}{4} = 15$

Henceforth, the value of A is 15.