Question

A paeticle takes 20 sec. to complete one full revolution on a circular path
radius 7.m How much distance and
go displacement will particle Cover in
is 10 second​

Answer 1

Explanation:

Answer:-

We know that:-

Speed = Distance / Time

So, we will be using the same formula.

Determination of distance:-

Speed = Distance / Time

Distance = Speed × Time

• Time is given as 20 seconds
• Distance will be 22/7 × 2 × 7
• = 44 m

Speed = Distance / Time

= 44 / 20

= 2.2 m/s

Now, we will be using the same formulae to determine the second distance.

Distance = Speed × Time

= 2.2 × 10

= 22 meters.

So, distance covered is 22 m.

NOTE THAT:-

Displacement will be zero as it it a circular motion.

$.$

Answer 2

$\huge{\boxed{\rm{Question}}}$

A particle takes 20 sec. to complete one full revolution on a circular path radius 7m How much distance and go displacement will particle cover in is 10 second.

$\huge{\boxed{\rm{Answer}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Time 20 seconds.

• Radius of circular path = 7 m.

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• How much distance and go displacement will particle cover in is 10 second ?

$\large{\boxed{\boxed{\sf{Solution}}}}$

• 22 metres is distance and go displacement will particle cover in is 10 second .

$\large{\boxed{\boxed{\sf{Using \: concepts}}}}$

$\large{\boxed{\boxed{\sf{Important \: to \: know}}}}$

• Distance = Speed × Time

• Speed = Distance / Time.

$\large{\boxed{\boxed{\sf{What \: does \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: concept \: 1st}}}}$

• This question says that a particle takes 20 seconds to complete a full revolution on a circular path of radius 7 metres . Afterthat it ask us to find how much distance and go displacement will particle cover in is 10 second ?

$\large{\boxed{\boxed{\sf{How \: to \: solve \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Let's \: see \: the \: procedure \: now}}}}$

• Firstly we have cleared that what does question say and now we have to see how to do this question so to solve this question firstly we have to use some formulas that we already know what are using formulas for this question. So, now coming to the question we have to use te formula 1stly we have to find the distance putting the values we get the distance ( 1st ) that is 44 metres afterthat we have to find the speed using the formula putting the values we get speed that is 2.2 m/sm Afterwards using the formula to find Distance again putting the values we get our final result that is 22 metres. Hence, 22 metres is distance and go displacement will particle cover in is 10 second .

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

✞ According to the question we already cleared that what is given or what to solve. Let see it again to understand properly ➝

• Time ( Given )

• Radius ( Given )

• Distance and go displacement will particle cover in is 10 second ( To find )

As we already know that ➝

• Speed = Distance / Time

✞ In question it is ask to find the distance nor speed so using the formula to find Distance and we already know what is the formula to find Distance let's see below ➝

• Distance = Speed × Time

✞ Let's solve it properly ➝

Firstly let us find ❛Distance❜

Using formulas we have to substitute the values and we get the following results ➝

➪ Distance = Speed × Time

➪ Distance = 22/7 × 7 × 2

( Cancelling 7 by 7 and multiplying 22 by 2 we get the following results )

➪ Distance = 22 × 2

➪ Distance = 44 m

$\bold{\green{\fbox{\green{Distance = 44 metres}}}}$

✞Now finding the ❛Speed❜ using formula

Using formulas we have to substitute the values and we get the following results ➝

➪ Speed = Distance / Time

➪ Speed = 44/20

➪ Speed = 22/10

➪ Speed = 11/5

➪ Speed = 2.2 m/s

$\bold{\green{\fbox{\green{Speed = 2.2 m/s}}}}$

Again let us find ❛Distance❜ again

Using same formula of finding distance we have to substitute the values and we get the following results ➝

➪ Distance = Speed × Time

➪ Distance = 2.2 × 10

➪ Distance = 22/10 × 10

( Cancelling 10 by 10 we get the following results )

➪ Distance = 22 metres.

$\bold{\green{\fbox{\green{Disatance = 22 metres}}}}$