Question

A page is selected at random from a book. The probability that the digit at units place of the page number chosen is less than 7 is​

Answer 1

S={0,1,2,3,4,5,6,7,8,9}

n(s)= 10

Event A= The page choosen bears no. less than 7 at its unit place

A={0,1,2,3,4,5,6}

n(A) = 7

Therefore, p(A) =n(a)/n(s)=7/10

Answer 2

The probability that the digit at units place of the page number chosen is less than 7 is​ 0.7 .

Explanation:

We know that the total number of digits in the number system = 10 ( 0 to 9)

i..e Possible outcomes for units place of the page number = 10

Numbers less than 7 =(0 , 1 , 2 , 3,4, 5 ,6) = 7

i.e.  Favorable outcomes =7

Now , the probability that the digit at units place of the page number chosen is less than 7 is​$\dfrac{Favorable \ outcomes}{Total\ outcomes}$

$=\dfrac{7}{10}=0.7$

Hence, the probability that the digit at units place of the page number chosen is less than 7 is​ 0.7 .

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