A paint in a certain container is sufficient to paint an equal to 9.375 sq m. How many bricks of dimensions 22.5cm, 10cm and 7.5cm can be painted from the available paint?
Answers
Answered by
52
hey there !!
the paint in container to paint an area = 9.375 m².
now ,
given ;- dimension of the brick to be painted are ;- 22.5cm ,10cm,7.5cm
therefore
TSA( total surface area ) of cuboid ( brick) = 2(lb+bh+lh)
TSA = 2(22.5×10+10×7.5+22.5×7.5)cm²
TSA = 2(225+75+168.75)cm²
TSA = 2×468.75
TSA = 937.5cm²
now , total surface area of the brick is 937.5cm²
converting it into m² = 937.5/100 = 9.375m²
now ,
no. of brick that will be painted bY using the paint = area of paint equal to / total surface aea of brick
no. of brick = 9.375m²/9.375m² = 1 brick
hence only a single brick can be painted by the paint left .
hope it helps !!
be brainly ♥
the paint in container to paint an area = 9.375 m².
now ,
given ;- dimension of the brick to be painted are ;- 22.5cm ,10cm,7.5cm
therefore
TSA( total surface area ) of cuboid ( brick) = 2(lb+bh+lh)
TSA = 2(22.5×10+10×7.5+22.5×7.5)cm²
TSA = 2(225+75+168.75)cm²
TSA = 2×468.75
TSA = 937.5cm²
now , total surface area of the brick is 937.5cm²
converting it into m² = 937.5/100 = 9.375m²
now ,
no. of brick that will be painted bY using the paint = area of paint equal to / total surface aea of brick
no. of brick = 9.375m²/9.375m² = 1 brick
hence only a single brick can be painted by the paint left .
hope it helps !!
be brainly ♥
Anonymous:
1 cm = 1/100 m.. hence 1cm^2 = 1/10000 m^2
Answered by
58
Heya!!
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Since paint in a certain container is sufficient to paint an equal to 9.375 m^2.
Let the number of bricks be n.
Total surface area of a brick =
2[(22.5)(10) + (10)(7.5) + (22.5)(7.5)]
= 2[225 + 75 + 168.75] cm^2
= 2(468.75)cm^2
= 937.50 cm^2
Hence 9.375 m^2 = n * 937.50 cm^2
=) 9.375* 10^4 cm^2 = n * 937.50 cm^2
=) 93750 = n * 937.50
=) 93750/937.50 = n
=) 100 = n
Hope it helps uh!!
-------------------------------------
Since paint in a certain container is sufficient to paint an equal to 9.375 m^2.
Let the number of bricks be n.
Total surface area of a brick =
2[(22.5)(10) + (10)(7.5) + (22.5)(7.5)]
= 2[225 + 75 + 168.75] cm^2
= 2(468.75)cm^2
= 937.50 cm^2
Hence 9.375 m^2 = n * 937.50 cm^2
=) 9.375* 10^4 cm^2 = n * 937.50 cm^2
=) 93750 = n * 937.50
=) 93750/937.50 = n
=) 100 = n
Hope it helps uh!!
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