Math, asked by renzjmr3, 1 year ago

A paint in a certain container is sufficient to paint an equal to 9.375 sq m. How many bricks of dimensions 22.5cm, 10cm and 7.5cm can be painted from the available paint?

Answers

Answered by Anonymous
52
hey there !!

the paint in container to paint an area = 9.375 m².

now ,

given ;- dimension of the brick to be painted are ;- 22.5cm ,10cm,7.5cm

therefore

TSA( total surface area ) of cuboid ( brick) = 2(lb+bh+lh)

TSA = 2(22.5×10+10×7.5+22.5×7.5)cm²

TSA = 2(225+75+168.75)cm²

TSA = 2×468.75

TSA = 937.5cm²

now , total surface area of the brick is 937.5cm²

converting it into m² = 937.5/100 = 9.375m²

now ,

no. of brick that will be painted bY using the paint = area of paint equal to / total surface aea of brick

no. of brick = 9.375m²/9.375m² = 1 brick

hence only a single brick can be painted by the paint left .

hope it helps !!

be brainly ♥

Anonymous: 1 cm = 1/100 m.. hence 1cm^2 = 1/10000 m^2
Anonymous: edit ur answer
Anonymous: ook
Anonymous: edit nhi kr saktaa kisi ne report kr diya .,,,, lol .....
Anonymous: lol #Himanahujha02.. uh did thanks by ur fake accounts xd
Answered by Anonymous
58
Heya!!

-------------------------------------

Since paint in a certain container is sufficient to paint an equal to 9.375 m^2.

Let the number of bricks be n.

Total surface area of a brick =

2[(22.5)(10) + (10)(7.5) + (22.5)(7.5)]

= 2[225 + 75 + 168.75] cm^2

= 2(468.75)cm^2

= 937.50 cm^2

Hence 9.375 m^2 = n * 937.50 cm^2

=) 9.375* 10^4 cm^2 = n * 937.50 cm^2

=) 93750 = n * 937.50

=) 93750/937.50 = n

=) 100 = n

Hope it helps uh!!
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