Question

A paint in a certain container is sufficient to paint an equal to 9.375 sq m. How many bricks of dimensions 22.5cm, 10cm and 7.5cm can be painted from the available paint?

Answer 1

hey there !!

the paint in container to paint an area = 9.375 m².

now ,

given ;- dimension of the brick to be painted are ;- 22.5cm ,10cm,7.5cm

therefore

TSA( total surface area ) of cuboid ( brick) = 2(lb+bh+lh)

TSA = 2(22.5×10+10×7.5+22.5×7.5)cm²

TSA = 2(225+75+168.75)cm²

TSA = 2×468.75

TSA = 937.5cm²

now , total surface area of the brick is 937.5cm²

converting it into m² = 937.5/100 = 9.375m²

now ,

no. of brick that will be painted bY using the paint = area of paint equal to / total surface aea of brick

no. of brick = 9.375m²/9.375m² = 1 brick

hence only a single brick can be painted by the paint left .

hope it helps !!

be brainly ♥

Answer 2

Heya!!

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Since paint in a certain container is sufficient to paint an equal to 9.375 m^2.

Let the number of bricks be n.

Total surface area of a brick =

2[(22.5)(10) + (10)(7.5) + (22.5)(7.5)]

= 2[225 + 75 + 168.75] cm^2

= 2(468.75)cm^2

= 937.50 cm^2

Hence 9.375 m^2 = n * 937.50 cm^2

=) 9.375* 10^4 cm^2 = n * 937.50 cm^2

=) 93750 = n * 937.50

=) 93750/937.50 = n

=) 100 = n

Hope it helps uh!!