Math, asked by priyanshukotiyal714, 5 months ago

a painting is made of 3 concentric square the side length of the smallest square is 5 cm the length of each outer square is 5 times the side length of each square just inside it what is the area of the painting

Answers

Answered by vaishu9620
1

Step-by-step explanation:

Area of painting is 15,625\hspace{0.1cm}cm^215,625cm

2

Given that a painting is made of 3 concentric squares.

Two or more squares are concentric when each square share the same centre or axis

Length of side of smallest square \hspace{0.1cm}=\hspace{0.1cm}5\hspace{0.1cm}cm=5cm

Also, side length of outer circle is 5 times the side length of square just inside it

Thus, the side length of middle square is calculated as

\begin{gathered}S_2= 5\hspace{0.1cm}cm\hspace{0.1cm}\times\hspace{0.1cm}5\\\\ S_2= 25\hspace{0.1cm}cm\end{gathered}

S

2

=5cm×5

S

2

=25cm

Similarly, length of outer square is calculated as

\begin{gathered}S_3= 25\hspace{0.1cm}cm\hspace{0.1cm}\times\hspace{0.1cm}5\\\\ S_3= 125\hspace{0.1cm}cm\end{gathered}

S

3

=25cm×5

S

3

=125cm

Now, Area of painting is calculated as

\begin{gathered}Area = (\,S_3)\,^2\\\\Area = 125^2\\\\Area = 15,625\end{gathered}

Area=(S

3

)

2

Area=125

2

Area=15,625

Hence, area of painting is 15,625\hspace{0.1cm}cm^215,625cm

2

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