a painting is made of 3 concentric square the side length of the smallest square is 5 cm the length of each outer square is 5 times the side length of each square just inside it what is the area of the painting
Answers
Step-by-step explanation:
Area of painting is 15,625\hspace{0.1cm}cm^215,625cm
2
Given that a painting is made of 3 concentric squares.
Two or more squares are concentric when each square share the same centre or axis
Length of side of smallest square \hspace{0.1cm}=\hspace{0.1cm}5\hspace{0.1cm}cm=5cm
Also, side length of outer circle is 5 times the side length of square just inside it
Thus, the side length of middle square is calculated as
\begin{gathered}S_2= 5\hspace{0.1cm}cm\hspace{0.1cm}\times\hspace{0.1cm}5\\\\ S_2= 25\hspace{0.1cm}cm\end{gathered}
S
2
=5cm×5
S
2
=25cm
Similarly, length of outer square is calculated as
\begin{gathered}S_3= 25\hspace{0.1cm}cm\hspace{0.1cm}\times\hspace{0.1cm}5\\\\ S_3= 125\hspace{0.1cm}cm\end{gathered}
S
3
=25cm×5
S
3
=125cm
Now, Area of painting is calculated as
\begin{gathered}Area = (\,S_3)\,^2\\\\Area = 125^2\\\\Area = 15,625\end{gathered}
Area=(S
3
)
2
Area=125
2
Area=15,625
Hence, area of painting is 15,625\hspace{0.1cm}cm^215,625cm
2