Question

a painting is to be painted on cardboard of length 12 cm and breadth 9 CM leave a margin of 1.5 cm from each side find the area of painting ​

Answer 1

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$\bf{{\underline{Given}}:}$

• Total length of the cardboard = 12cm
• Total breadth of the cardboard = 9cm

$\bf{{\underline{To~find}}:}$

• The area of the painting region leaving a margin of 1.5cm from each side

$\bf{{\underline{Solution}}:}$

• When leaving the margin of 1.5cm from each side, the length and breadth gets reduced to 9cm and 6cm respectively.
• ie., Length = 9cm　Breadth = 6cm

$\sf Area \: of \: a \: rectangle = l \times b \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf = 9 \times 6 \: \: \: \: \: \: \: \\ \sf = \purple{ \underline{ \boxed{ \bf 54 {cm}^{2} }}} \:$

$\bf\therefore{{\underline{Required~answer}}:}$

• The area of region to be painted is ${\purple{ \underline{ \boxed{ \bf 54 {cm}^{2} }}}}$

$\bf{{\underline{Note}}:}$

• You may refer the attachment for diagram for better understanding !

Answer 2

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Length of painted cardboard=8 cm and breadth of painted card =5cm

Since, there is a margin of 1.5cm long from each of its side.

Therefore reduced length

=8−(1.5+1.5)=8−3=5cm

And reduced breadth

=5−(1.5+1.5)=5−3=2cm

∴ Area of margin=Area of cardboard(ABCD)−Area of cardboard(EFGH)

=(AB×AD)−(EF×EH)

=(8×5)−(5×2)

=40−10

=30cm²

Thus, the total area of margin is 30cm² .

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