a painting of length 70 cm is to be hung on a wall of length 9 m exactly in the middle. where should the nail be put to hung the painting?
Answers
4.5 meters
The nail should be put at 4.5 meters
Step-by-step explanation:
answer:
volume of the ball: 1000 c-cmradius of the ball:
r = 10 \Bigg({ \frac{3}{4\pi} }\Bigg)^{ \frac{1}{3} } \: cm \\
Would the surface of the water be 4cm below the top of the tank?
No
Step-by-step explanation:
A glass tank is 25cm long, 20cm wide, 30cm high and contains water. The surface of the water is 5 cm below the top of the tank.
Water tank is in the shape of cuboid:
Volume of cuboid:
l \times b \times h \\ \\
After a solid metal spherical ball B1 has carefully been placed into the tank, the surface of the water is 3cm below the top of the tank.
Change in height of water level after placing the spherical ball in it = 2 cm
Volume of water raised = Volume of spherical Ball
10.1) Calculate the volume of the ball
answer:
= 25 \times 20 \times 2 \\ \\ = 25 \times 40 \\ \\ volume \: of \: ball B1= 1000 \: {cm}^{3} \\
10.2) Calculate the radius of the ball. Leave your answer in terms of \pi and a surd if necessary.
answer:
\frac{4}{3} \pi {r}^{3} = 1000 \\ \\ {r}^{3} = \frac{1000 \times 3}{4\pi} \\ \\ r = 10 \Bigg({ \frac{3}{4\pi} }\Bigg)^{ \frac{1}{3} } \: cm \\
10.3) Suppose the radius of a second solid metal ball, B2; is half the radius of ball B1: Suppose ball B2 was put into the tank of water instead of ball B1: Would the surface of the water be 4cm below the top of the tank? Explain your answer
answer: B2 is half the radius of B1
r_1 = 10 \Bigg({ \frac{3}{4\pi} }\Bigg)^{ \frac{1}{3} } \: cm \\ \\ r_2 = 5 \Bigg({ \frac{3}{4\pi} }\Bigg)^{ \frac{1}{3} } \: cm \\ \\ volume \: of \: B2 = \frac{4}{3} \pi\Bigg( {5 \Big({ \frac{3}{4\pi} }\Big)^{ \frac{1}{3} }}\Bigg)^{3} \\ \\ = \frac{4\pi}{3} \times ({5})^{3} \times \frac{3}{4\pi} \\ \\ = 125 \: {cm}^{3} \\ \\
On putting that ball let the change in height of water is h,so
125 = 20 \times 25 \times h \\ \\ h = \frac{125}{20 \times 25} \\ \\ h = \frac{5}{20} \\ \\ h = \frac{1}{4} \: cm \\ \\ = 0.25 \: cm \\
No,the surface of water is 4.75 cm below.
Hope it helps you.