Question

A pair of a supplementary angles are in the ratio 3:2,Find them​

Answer 1

Answer:

Answer:

✶⊶⊷⊶⊷❍ ❥ ❍⊶⊷⊶⊷✶

$\large\green{\mid{\fbox{\tt{Ꭲօ թɾօѵҽ}}\mid}}$

$\frac{sinθ}{1+cosθ}+\frac{1+cosθ}{sinθ}=2cosecθ$

$\large\red{\mid{\fbox{\tt{รοℓυƭเօɳ}}\mid}}$

$\large\pink{\mid{\fbox{\tt{ᏞᎻร}}\mid}}$=

$⟹\sf\bold{\blue{\frac{sinθ}{1+cosθ}+\frac{1+cosθ}{sinθ}}}$

$⟹\sf\bold{\blue{\frac{sin²+(1+cosθ)²}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{sin²+1+cos²θ+2cosθ}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{sin²+cos²θ+1+2cosθ}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{2+2cosθ}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{2(1+cosθ)}{(1+cosθ)sinθ}}}$

$⟹\sf\bold{\blue{\frac{2}{sinθ}}}$

$⟹\large\pink{\mid{\fbox{\tt{2.coseθ}}\mid}}$

$\large\pink{\mid{\fbox{\tt{ᏞᎻร=ƦᎻร}}\mid}}$

✶⊶⊷⊶⊷❍ ❥ ❍⊶⊷⊶⊷✶

_________________________________⠀⠀⠀⠀

⠀⠀⠀ $\large\green{\mid{\fbox{\tt{❥ϐℓυєᴇყεร}}\mid}}$

_________________________________⠀

Answer 2

SUPPLEMENTARY ANGEL ARE THOSE HAVING 180° SUM

LET 3x AND 2x BE ANGEL

2x+3x=180°

5x=180

x=36°

ANGEL

2x= 2×36=72

3x=3×36=108