Question

A pair of adjacent coils has a mutual inductance of 0.98 H. Determine the average emf induced in the secondary circuit when the current in the primary circuit changes from 0 A to 9.88 A in a time interval of 0.0350 s

Answer 1

we know,

$e = -m \frac{di}{dt} \\ = > e = - 0.98 \frac{9.88}{0.0350} \\ = > e = 276.64$

Ans.

Answer 2

Answer:

we know,

\begin{lgathered}e = -m \frac{di}{dt} \\ = > e = - 0.98 \frac{9.88}{0.0350} \\ = > e = 276.64\end{lgathered}

e=−m

dt

di

=>e=−0.98

0.0350

9.88

=>e=276.64