Question

 A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?


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Answer 1

Answer:

Explanation:

Solution,

Here, we have

Mutual inductance, µ = 1.5 H

Initial current, I₁ = 0 A

Final current, I₂ = 20 A

Then,

Change in current = 20 - 0 = 20 A.

Now,

Time taken, t = 0.5 seconds

Here, we have

Induced emf, e = dΦ/dt ...... (i)

Here, dΦ s the change in the flux linkages with the coil.

Here, we get from eq (i),

⇒ dΦ/dt = µ (dl/dt)

⇒ dΦ = 1.5 × 20

⇒ dΦ = 30 Wb.

Hence, the change in the flux linkage is 30 Wb.

Answer 2

Answer:

The change in the flux linkage is 30 Wb.

Explanation:

Mutual inductance, µ = 1.5 H

Initial current (I1) = 0 A

Final current (I2) = 20 A

Change in current = 20 - 0 = 20 A

Time taken (t) = 0.5s

Induced emf (e) = dΦ/dt ...... (i)

dΦ s the change in the flux linkages with the coil.

From eq (i)

→ dΦ/dt = µ (dl/dt)

→ dΦ = 1.5 × 20

→ dΦ = 30 Wb.

Hence,

The change in the flux linkage is 30 Wb.