A pair of adjacent sides of a rectangle is in the ratio of 5:12. If the length of the diagonal is 26cm. Find the lengths of the sides and perimeter of the rectangle
Answers
Answered by
69
Let the sides be 5x and 12x. Now since diagonal is of 26 cm therefore by Pythagoras theorem
26^2= (5x)^2 + (12x)^2
on solving this we will get
x= 2
so, 5x= 10 cm
& 12x= 24 cm
and so perimeter will be sum of all sides
= 68cm
26^2= (5x)^2 + (12x)^2
on solving this we will get
x= 2
so, 5x= 10 cm
& 12x= 24 cm
and so perimeter will be sum of all sides
= 68cm
nainapathak:
But how there will be x=2
Please explain
Oo I got it
Answered by
42
AB^2+AD^2=BD^2
12x^2+5x^2=26^2
144x^2+25x^2=676
169x^2=676
x^2=676/169
x=2
:AB=5×2=10
:AD=12×2=24
Perimeter=2(L+B)
Perimeter=2(10+24)
Perimeter=2×34
Perimeter=68cm
12x^2+5x^2=26^2
144x^2+25x^2=676
169x^2=676
x^2=676/169
x=2
:AB=5×2=10
:AD=12×2=24
Perimeter=2(L+B)
Perimeter=2(10+24)
Perimeter=2×34
Perimeter=68cm
Similar questions