A pair of adjacent sides of rectangle are in the ratio 3:4.If it's diagonal is 20cm long,f Ind the length of the sides and perimeter of the rectangle.
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Let us consider the triangle formed by the diagonal of length 20 cm.
Using the ratio 3:4 =b:l
let the common multiplier be 'x'
Therefore,
Length = 4x
Breadth = 3x
Using Pythagoras theorem
![{diagonal}^{2} = {3x}^{2} + {4x}^{2} {diagonal}^{2} = {3x}^{2} + {4x}^{2}](https://tex.z-dn.net/?f=+%7Bdiagonal%7D%5E%7B2%7D++%3D++%7B3x%7D%5E%7B2%7D++%2B++%7B4x%7D%5E%7B2%7D+)
![400 = 9 {x}^{2} + 16 {x}^{2} 400 = 9 {x}^{2} + 16 {x}^{2}](https://tex.z-dn.net/?f=400+%3D+9+%7Bx%7D%5E%7B2%7D++%2B+16+%7Bx%7D%5E%7B2%7D+)
![400 = 25 {x}^{2} 400 = 25 {x}^{2}](https://tex.z-dn.net/?f=400+%3D+25+%7Bx%7D%5E%7B2%7D+)
![\frac{400}{25 } = {x}^{2} \frac{400}{25 } = {x}^{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B400%7D%7B25+%7D++%3D++%7Bx%7D%5E%7B2%7D+)
The common multiplier is 4.
Therefore the dimensions of the rectangle is
3x = 3 × 4 = 12 cm ...... Breadth
4x = 4 × 4 = 16 cm ...... Length
Perimeter is 2(l + b)
2(28)
56 cm
Using the ratio 3:4 =b:l
let the common multiplier be 'x'
Therefore,
Length = 4x
Breadth = 3x
Using Pythagoras theorem
The common multiplier is 4.
Therefore the dimensions of the rectangle is
3x = 3 × 4 = 12 cm ...... Breadth
4x = 4 × 4 = 16 cm ...... Length
Perimeter is 2(l + b)
2(28)
56 cm
surendrasenapati:
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