Question

A pair of coin is tossed one time.Find the probability of (i)getting at least two heads (ii)getting exactly two tails (iii)getting at most two tails​

Answer 1

i) P(Getting exactly two heads) = 3 / 8

(ii) P(Getting at least two heads) = 1 / 2

(iii) P(Getting at least two heads) = 1 / 2

Step-by-step explanation:

Possible outcomes when three coins are tossed together:

= 2 * 2 * 2 = 8 Possible Outcomes

Always keep in mind this formula while calculating Probability of an event:

(i) No of possible outcomes for getting exactly two heads = HHT, HTH and THH.

3 possible outcomes for getting exactly two heads.

P(Getting exactly two heads) = 3 / 8

(ii) No of possible outcomes for getting at least two heads = HHT, HTH, THH and HHH.

4 possible outcomes for getting at least two heads.

P(Getting at least two heads) = 4 / 8

= 2 / 4

= 1 / 2

(iii) No of possible outcomes to get at least two tails = TTH, THT, HTT and TTT.

4 possible outcomes to get at least two tails.

P(Getting at least two tails) = 4 / 8

= 2 / 4

= 1 / 2