A pair of dice are thrown what is the probability of getting (a) a doublet
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Answered by
2
Hey!
As per the question,
Favorable outcome possibility={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6.
Total outcome= 36 as their are two dices.
Hence probability of a doublet = favorable outcome/total outcome.
= 6/36.
=1/6.
Hope it helps.
As per the question,
Favorable outcome possibility={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6.
Total outcome= 36 as their are two dices.
Hence probability of a doublet = favorable outcome/total outcome.
= 6/36.
=1/6.
Hope it helps.
Answered by
4
Total number of outcome = 36
probablity of getting a doublet will be = (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)
Probablity(getting a doublet) = 6/36 = 1/6
Hope this helps :-)
probablity of getting a doublet will be = (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)
Probablity(getting a doublet) = 6/36 = 1/6
Hope this helps :-)
Anonymous:
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