Question

A pair of dice is rolled. If the sum on the dice is 9. Find the probability that one of dice showed 3.
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Answer 1

Answer:

1/2

Step-by-step explanation:

F. outcomes for first die. is 4,5,6

Total number of outcomes are= 6

probablity that comes = 3/6

=1/2 ans.

I hope it's helpful to you.......

Answer 2

Answer:

= 1/18

Step-by-step explanation:

Given that , a pair of dice is rolled.

To find the probability that one of dice shows 3.

So,

PROBABILITY = $\frac{No. ~of ~favourable~outcomes}{Total ~number ~of~outcomes}$

Total number of outcomes when a pair of dice is rolled = 36

The sum on the both dice is 9 are (3,6) , (4,5) , (5,4) , (6,3).

No. of favourable outcomes is the rolled pair dice sum is 9 and at least one dice 3 = ( 3,6 ) and ( 6,3 )

                 = 2

Probability that one dice showed 3 =$\frac{2}{36}$

                       

                                                           = $\frac{1}{18}$

Therefore, the 1/18 is probability .

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