Question

a pair of dice is thrown 3 times.If getting of 10 as a sum is a success.find the probability distribution of number of success.

Answer 1

when a pair of dice is thrown
n(S) =36
it is thrown 3 times
then n(S)= 108
number OF GETTING 10 when thrown once = 3
then number of getting 10 when thrown thrice = 9
probality of getting 10 when thrown thrice =9/108
=1/12

Answer 2

Answer:

PROBABILITY DISTRIBUTION:-

(0                 1                   2                    3)

(1331/1728   363/1728   33/1728   1/1728)

Answer:-

n=3

X denotes the sum of 10 so,

x={(6,4),(4,6),(5,5)}

P(x)=3/36=1/12

therefore 1/12 =p

q=1-1/12=11/12

Now,We know that

ncr(p)^r(q)^n-r

P(x=0)=3c0 1/12^0  11/12^3=1331/1728

P(x=1)=3c1 1/12^1  11/12^2=363/1728

P(x=2)=3c2 1/12^2 11/12^1=33/1728

P(x=3)=3c3 1/12^3 11/12^0=1/1728

Step-by-step explanation:

n denotes number of dice thrown

p denotes probability that the sum is 10

q denotes probability that it is not sum=10