Question

a pair of dice is thrown 4 times . if getting a doublet is considered a sucess , find the probability of two successes.​

Answer 1

The experiment is to toss a pair of dice (n=4) times. Getting a doublet is considered a success. It is a case of Bernoulli trials.

When a pair of dice is thrown once, the number of possible outcomes = 6×6=36.

The number of possible doublets in this case is :

{(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

P(getting a doublet on a roll of two dice) = p=

36

6

=

6

1

P(not getting a doublet ) = q=1−p=

6

5

X is a binomial distribution.

The experiment is to toss a pair of dice (n=4) times. Getting a doublet is considered a success. It is a case of Bernoulli trials.

When a pair of dice is thrown once, the number of possible outcomes = 6×6=36.

The number of possible doublets in this case is :

{(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

P(getting a doublet on a roll of two dice) = p=

36

6

=

6

1

P(not getting a doublet ) = q=1−p=

6

5

X is a binomial distribution.

Here, n=4,p=

6

1

,q=

6

5

Here, n=4,p=

6

1

,q=

6

5