Question

A pair of dice is thrown and sum of dice come up multiple of 4 then find probability that at least one dice shows four?
2/7
4/9
1/9
5/8​

Answer 1

Answer:

There are six faces for each of two dice, giving 36 possible outcomes. If the two dice are fair, each of 36 outcomes is equally likely. Three outcomes sum to 4: (1+3), (2+2) and (3+1). Probability of getting a sum of 4 on one toss of two dice is 3/36, or 1/12.

Step-by-step explanation:

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Answer 2

Given :-

◉ A pair of dice is thrown and sum of dice come up multiple of 4.

To Find :-

◉ Probability that atleast one dice shows four.

Solution :-

Before getting into the solution of this question, Let us first write the sample space:

11 12 13 14 15 16

21 22 23 24 25 26

31 32 33 34 35 36

41 42 43 44 45 46

51 52 53 54 55 56

61 62 63 64 65 66

To Be Noted :-

Because there are two dices, Hence possible outcomes is 6ⁿ which is 36 ; n = number of dice.

So, First step is to find all the outcomes whose sum is multiple of 4 from the possible outcomes, which are:

13 22 26 31

35 44 53 62

66

We find that, There is only one outcome among possible outcomes whose sum is a multiple of 4 and It contains the digit 4.

⇒ Probability = Favourable Outcomes / Possible Outcomes

∴ Probability = 1 / 9

Hence, Option (3) is correct.