A pair of dice is thrown once find probability of getting anodd no. And a total of 8
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the possibility of getting an odd no on one side
possible outcome =(1,6),(3,6),(5,6)
(1,5),(2,5),(3,5),(4,5),(5,5),(6,5)
(1,4),(3,4),(5,4)
(1,3),(2,3),(3,3),(4,3),(5,3),(6,3)
(1,2),(3,2),(5,2)
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
probability = 27/36
possiblity of getting a sum of 8
possible outcome - (2,6),(3,5),(4,4),(5,3),(6,2)
probability =5/36
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