Question

A pair of dice is thrown once. Find the probability of getting (i) even number on each dice (ii) a total of 9​

Answer 1

Step-by-step explanation:

(1) 1/2

(2) 1/3

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Answer 2

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A pair of dice is thrown once. Find the probability of getting (i) even number on each dice (ii) a total of 9..

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Total Outcomes of two dice=36

↦That are :. (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)...

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The numbers that are divisibke by 2 are known as Even Numbers...

For Eg:. 4,8,10 etc..

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(i) Total Outcomes= 9

↦That are :. (2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)

Probability ⇒ $\frac{No.\:of\:Fav.\:Outcomes}{Total.\:no\:of\:Outcomes}$

↦$\frac{9}{36}$

↦$\cancel\frac{9}{36}⇒\frac{1}{4}$

(ii) Total Outcomes = 4

↦That are:. (3,6) (4,5) (5,4) (6,3)

Probability ⇒$\frac{No.\:of\:fav\:Outcomes}{Total\:no.\:of\:Outcomes}$

↦$\frac{4}{36}$

↦$\cancel\frac{4}{36}⇒\frac{1}{9}$