Question

A pair of dice is thrown once . find the probability of getting
1. 8 as a sum
2. the same no. on each dice
3.a double of odd numbers
4.a sum less than or equal to 10
5. a sum greater than 9
6. a sum less than 7
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Answer 1

Answer:

1. P(sum as 8)= $\frac{5}{36\\}$

2. P (same number)= $\frac{6}{36}$ = $\frac{1}{6}$

3. P (doublet of odd no.) = $\frac{3}{36}$ = $\frac{1}{12}$

4. P (sum $\leq$ 10) = $\frac{33}{36}$ = $\frac{11}{12}$

5. P (sum greater than 9) = $\frac{10}{36}$ = $\frac{5}{18}$

6. P ( sum less than 7 ) = $\frac{15}{36}$ = $\frac{5}{12}$