Math, asked by Mbappe007, 7 hours ago

A pair of dice is thrown once.find the probability of getting a)an even number on the first die b)the number 4 on one die atleast c)the sum of the numbers is a multiple of 3​

Answers

Answered by princekumar8b31
1

Step-by-step explanation:

The total number of possible outcomes is 36.

i.e., n(S)=36

Let A: getting an even number on the first die

n(A)=18

B=sum as 8=$$(2,6),(6,2),(3,5),(5,3),(4,4)

n(B)=5

n(A∩B)=3

∴ Required probability =

n(S)

n(A)+n(B)−n(A∩B)

=

36

20

=

9

5

Answered by sanjaykrishnaamenapp
2

Answer:

A pair of dice is thrown once.find the probability of getting a)an even number on the first die b)the number 4 on one die atleast c)the sum of the numbers is a multiple of 3

Step-by-step explanation:

shari anna ok full set

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